Find where certain sequence of true/falses is placed inside a logical array

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Hello!
Assume that I have the following logical array:
x=[false;false;true;true;true;true;true;false;true;true;true]'
x = 1×11 logical array
0 0 1 1 1 1 1 0 1 1 1
I would like to construct a logical array which returns true at the index where the sequence [true;false;true] is found
Hence the result would look like this
result=[false;false;false;false;false;false;true;false;false;false;false]'
result = 1×11 logical array
0 0 0 0 0 0 1 0 0 0 0
Hope that the question is clear, thank you!

采纳的回答

David Hill
David Hill 2022-10-13
x=[false;false;true;true;true;true;true;false;true;true;true]';
f=strfind(x,[1 0 1]);
result=zeros(size(x));
result(f)=1
result = 1×11
0 0 0 0 0 0 1 0 0 0 0
  1 个评论
Enrico Gambini
Enrico Gambini 2022-10-13
编辑:Enrico Gambini 2022-10-13
Thank you!
For my purposes I would slightly change the code like this:
x=[false;false;true;true;true;true;true;false;true;true;true]';
f=strfind(x,[1 0 1]);
result=false(size(x));
result(f)=true
result = 1×11 logical array
0 0 0 0 0 0 1 0 0 0 0

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