Function that produce an uniform random numbers for loop error

1 次查看(过去 30 天)
Hi i'm having an issue in my for loop
i',m trying to make a function that produce an uniform random numbers but no matter what i adjust i keep getting the same error
clear
clc
%N=input('sequence_length')
N=5000
N = 5000
MinSec = fix(clock);
seed = 100*MinSec(5) + MinSec(6);
Urand = myrandi(seed,N);
la = 65539
P = 2.1475e+09
Index exceeds the number of array elements. Index must not exceed 1.

Error in solution>myrandi (line 33)
Urand(i)= mod(la*seed(i-1),P);
%b
%Y=ones(size(Urand));
subplot(2,1,1)
hist(Urand)
%% Task 1: : the Linear Congruential Generator (LCG)
v = rand(1,N);
%u=u./max(u);
subplot(3,2,2);
hist(v,100);
title(subplot(2,1,2),'Uniform random: rand()');
%Function that produce an uniform random numbers
%Using the technic of LCG r(k) = [lambda*r(k-1)]modulo(P)
function Urand = myrandi(seed,sequence_length)
la=65539
N=sequence_length;
P=2^31
%change N accordingly
%part a
Urand=zeros(1,N);
Urand(1)=seed;
for i=2:N
Urand(i)= mod(la*seed(i-1),P);
end
Urand=Urand/65539;
%printing genetrated vector, after dividing by 6655
if N<=50 %will print numbers only
if N<=50
disp(['for N = ',num2str(N)])
disp(Urand)
end
end
end%function myrand

采纳的回答

KSSV
KSSV 2022-10-14
This line:
Urand(i)= mod(la*seed(i-1),P);
Your seed is a scalar, it has sinlge value. You are trying to extract more number by indexing it and treating it as a vector. This is the error.
Do you mean to use:
Urand(i)= mod(la*seed*(i-1),P);
  3 个评论
Faisal Al-Wazir
Faisal Al-Wazir 2022-10-14
yes now it works
clear
clc
%N=input('sequence_length')
N=5000
N = 5000
MinSec = fix(clock);
seed = 100*MinSec(5) + MinSec(6);
Urand = myrandi(seed,N);
la = 65539
P = 2.1475e+09
Urand = 1×5000
0 0.0929 0.1859 0.2788 0.3717 0.4647 0.5576 0.6505 0.7434 0.8364 0.9293 0.0222 0.1152 0.2081 0.3010 0.3940 0.4869 0.5798 0.6727 0.7657 0.8586 0.9515 0.0445 0.1374 0.2303 0.3233 0.4162 0.5091 0.6020 0.6950
%b
%Y=ones(size(Urand));
subplot(3,2,1)
hist(Urand)
%% Task 1: : the Linear Congruential Generator (LCG)
v = rand(1,N);
%u=u./max(u);
subplot(3,2,2);
hist(v,100);
title(subplot(3,2,2),'Uniform random: rand()');
%Function that produce an uniform random numbers
%Using the technic of LCG r(k) = [lambda*r(k-1)]modulo(P)
function Urand = myrandi(seed,sequence_length)
la=65539
N=sequence_length;
P=2^31
%change N accordingly
%part a
Urand=zeros(1,N);
seed(1)=seed;
for i=2:N
Urand(i)= mod((la*seed*(i-1)),P);
end
Urand = Urand./(P-1)
end%function myrand

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Timing and presenting 2D and 3D stimuli 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by