How to create a 2D reverse matrix
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Hi, I'm wondering how to create a reversed numerical matrix. For example, if I have a convolution h[j,k] = [1 2 3; 4 5 6; 7 8 9] then reverse h[j,k] = h[-j-k] = [9, 8 7; 6 5 4; 3 2 1]. I'm aware that you can use rot90(h, 2) and a combination of fliplr and flipud to get the results of reverse h, but are there any more direct ways to get the reverse matrix? Thanks.
采纳的回答
Since you are willing to use tools like fliplr (as opposed to flip. Anyway, fliplr and flipud are more descriptive, so I kind of like them.) But then what is wrong with the simple:
H = [1 2 3; 4 5 6; 7 8 9]
Hflip = fliplr(flipud(H))
which requires only 2 calls. Or, if you like a matrix multiply, you could do it as:
trans = flip(eye(3));
trans*H*trans
更多回答（1 个）
a=[1 2 3; 4 5 6; 7 8 9];
reshape(flip(a(:)),size(a))
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