Extract numbers from char type
显示 更早的评论
how can I extract the numbers from a character array value of '4.64 km' and return them as 4.64?
采纳的回答
Probably the easiest way —
s = '4.64 km';
c = regexp(s, '\d*\.\d*|\d*', 'match')
n = str2double(c)
EDIT — (18 Oct 2022 at 19:38)
In the event any of the numbers are negative —
s = '4.64 -42 2 -3.14 km';
c = regexp(s, '(\-\d*|\d*)\.\d*|(\-\d*|\d*)', 'match')
n = str2double(c)
.
4 个评论
Walter Roberson
2022-10-19
-?(\d+\.\d*¦\.\d+)
Star Strider
2022-10-19
Noted!
I had forgotten that syntax and couldn’t find it in the documentation.
Walter Roberson
2022-10-19
darn I forgot the case of no period
Star Strider
2022-10-19
I saw that and wondered, however I did not change my answer, and just learned from the important parts of your syntax.
更多回答（2 个）
Or, in one line of code:
s = '4.64 km';
num = sscanf(s, '%f') % num will be a double
1 个评论
Walter Roberson
2022-10-18
Yes this works well when the number is at the beginning. You can also put literal text into the format if you expect an exact match.
The suggestions to use regexp to extract the text of the number work well when you need flexibility.
In cases where you have tables of text see textscan() which can be used on a character vector that has embedded newlines.
a='4.65 km';
r=regexp(a,'\d*[.]*\d*','match');
str2num(r{1})
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