Calling nested functions inside a parfor loop

Question

Antoine GUELLIER 2015-3-14

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/183103-calling-nested-functions-inside-a-parfor-loop

评论： Hung Dao 2021-7-6

Hello,

I am trying to parallelize a program. I am experiencing issues with a parallel for and nested functions. My main function contains a big parfor loop, and several nested functions. These nested function access (both read and write) the variables declared in the main function. Without parallelism, everything works fine: my nested function do their job and update the variables in my main function (as it is supposed to be). This is true whether I call the nested function directly or using a handle. However, when I switch to a parfor (and thus use handles, as it should be), and make so that no error appear, the nested function no longer updates the variables from the main function. Said otherwise, MATLAB does not detect any error, but my program doesn't really do anything!

Below is a representative example:

function garbage
    accumulator = [];
      handleFoo = @foo;
      for i=1:10
          aux = i*5;
          handleFoo(aux);
      end
      accumulator
      function foo(n)
          accumulator(end+1) = n;
      end
  end

Running this program as-is will result "accumulator" equal to 1:10. But simply changing the for loop to a parfor will resut in an empty array.

Is this the expected behavior of MATLAB? Is there away to work around this? I could not find help on this specific question anywhere.

Thank you Antoine

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Answer 1

Edric Ellis 2015-3-16

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/183103-calling-nested-functions-inside-a-parfor-loop#answer_171482

Yes, this is expected behaviour - the MATLAB workers operating on the body of your parfor loop are separate MATLAB processes, and they do not share thing like handle variables, or nested function workspaces. All data that flows into and out from a parfor loop must go through explicit variable transfers.

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Antoine GUELLIER 2015-3-16

编辑：Antoine GUELLIER 2015-3-16

Thank you! I supposed it was this way, but I didn't see this fact explicited anywhere.

Hung Dao 2021-7-6

Is there a solution for this? I am having a similar issue. I want to call a function f inside a parfor loop. I am using feval(f, arguments of f). The function f calls another functions. Without parfor, it works OK but with parfor it results in an error.

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