for loop, in irregular numbers clusters?

Question

Jong Yeon 2022-10-20

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1831193-for-loop-in-irregular-numbers-clusters

评论： Bjorn Gustavsson 2022-10-21

采纳的回答： Bjorn Gustavsson

i have to make a loop code, but the loopcounter (numbers) very irregular.

for an example: 1 2 3 4 6 7 8 10 12 13 14 15 16 18 19 20.

if i do it in bash script, the code would be like : [for idx in {1..8} 10 {12..16} {18..20}; do echo $idx; done;]

is there good way to code this case with matlab?

(above line is just for an example. in my practical job, the loop counter would go up to thousands.)

please share some wisdom. thank you.

p.s. : actually, in above example, when i loop from 1 to 20, there is a list of numbers "not to do" like [5, 9, 11, 17].

maybe i should make a array [1 ... 20] and delete out "not to do numbers" (5,9, 11,17) from loop...? i don't know how;;

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Answer 1

Bjorn Gustavsson 2022-10-20

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编辑：Bjorn Gustavsson 2022-10-20

在 MATLAB Online 中打开

You will have these lists of "todos" and "not-todos" from somewhere outside, since, as you write, you can't type down all the numbers.

If you have the explicit array of numbers from outside it should be as simple as this:

function disp_orders(idx_to_do)
v = idx_to_do(:)';
for k = v
  disp("Now serving order #" + k)
end

If you have the range of the numbers and an array of numbers to skip you can modify this easily:

function disp_orders(idx_range,idx_to_skip)
v = min(idx_range):max(idx_range); % Generate the full list
v = setdiff(v,idx_to_skip)         % remove those not wanted
for k = v
  disp("Now serving order #" + k)
end

Here you will obviously have to use the code-snippets inside the functions as suitable for your problem. This specifically addresses your question.

HTH

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Jong Yeon 2022-10-21

ah-ha. "setdiff( )" was the sweetie for me! thank you;;;

Bjorn Gustavsson 2022-10-21

You're welcome, happy that it helped.

There must be some kind of N%-M% rule for matlab-use, perhaps 80% of the time an existing matlab-function solves at least 80% of the problem - sometimes it is just a question about how to find them.

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Answer 2

Steven Lord 2022-10-20

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https://ww2.mathworks.cn/matlabcentral/answers/1831193-for-loop-in-irregular-numbers-clusters#answer_1079428

在 MATLAB Online 中打开

v = [1 2 3 4 6 7 8 10 12 13 14 15 16 18 19 20];
for k = v
    disp("Now serving order #" + k)
end
Now serving order #1
Now serving order #2
Now serving order #3
Now serving order #4
Now serving order #6
Now serving order #7
Now serving order #8
Now serving order #10
Now serving order #12
Now serving order #13
Now serving order #14
Now serving order #15
Now serving order #16
Now serving order #18
Now serving order #19
Now serving order #20