creating a frame
显示 更早的评论
Hi
Want to clarify a simple doubt I have, which was posted earlier, but had not got a reply.
Does
a = randn(20,20)
imshow(a, [ ])
create a frame with 20x20 pixel, size of each pixel being 1x1, the values of the pixels are Gaussian and the intensity(values of the pixels) are gray linear scale?
Does
a = 3*randn(20,20)
imshow(a, [ ])
create a frame with the same specifications, now that the values are Gaussian with a standard deviation of '3'??
Awaiting your advice
Cheers
P
回答（1 个）
Walter Roberson
2011-10-14
0 个投票
No, and No.
randn() cannot produce numbers beyond +/- realmax. No fixed finite range of numbers can have a gaussian distribution. A gaussian distribution has an infinite tail, always.
类别
在 帮助中心 和 File Exchange 中查找有关 Data Distribution Plots 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
