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one equation with one unknown variable

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Lojzika
Lojzika 2015-3-15
评论： Konstantinos Sofos 2015-3-15
Hello,
I want to solve equation with one unknown variable (x).
Matlab code: Editor: function y = f(x)
y=(18/5)*((1-x)^(-1/6))-(162/29)*((1-x)^(-1/9));
Command window: x=fzero(@f,[0,1])
(x should be between 0 and 1)
And the error is: ??? Error using ==> fzero at 283 The function values at the interval endpoints must differ in sign.
What should I do to solve that equation correctly?
And help will be appreciated.

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采纳的回答

Konstantinos Sofos
Konstantinos Sofos 2015-3-15
编辑：Konstantinos Sofos 2015-3-15
Hi,
fzero checks that fun(x0(1)) and fun(x0(2)) have opposite signs, and errors if they do not. In you example the upper bound gives NaN
>> y=@(x)(18/5)*((1-x)^(-1/6))-(162/29)*((1-x)^(-1/9))
y =
@(x)(18/5)*((1-x)^(-1/6))-(162/29)*((1-x)^(-1/9))
>> y(0)
ans =
-1.9862
>> y(1)
ans =
NaN
Does this help you how to continue program with fzero error ?
Regards

更多回答（1 个）

Roger Stafford
Roger Stafford 2015-3-15
I would recommend that you alter the interval:
x=fzero(@f,[0,.999999]);
There is an easier way of solving it. Substitute t = (1-x)^(-1/18) and get an equation in t, which can be easily solved. From that you can get back to a solution for x.
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John D'Errico
John D'Errico 2015-3-15
I am confused as to why you would accept the other answer as this is so clearly the correct one. Oh well, Roger's answer got my vote.
Konstantinos Sofos
Konstantinos Sofos 2015-3-15
@John D'Errico could you explain us also why my answer is not valid or the correct one? Do we have any competition here or shall we try to provide our view? I am sorry for your comment...

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