compute the indefinite integral

6 次查看（过去 30 天）
William Lancelot
William Lancelot 2022-10-23
回答： Torsten 2022-10-23
how can I compute the indefinite integral of an anonymous function?
f=1010;
d= 0:0.0001:8;
z = @(d) sawtooth(2*pi*f*d+pi,0);
  3 个评论
显示 1更早的评论
William Lancelot
William Lancelot 2022-10-23
thank you for your reply
I did compute the integral of the above function symbolically using syms and int and a bunch of heavisides. However, I can't use anything symbolic when I try to import the result in Simulink. I converted the symbolic expression with matlabFunction, but I do not know how to use it in Simulink
William Lancelot
William Lancelot 2022-10-23
I am trying to plot the above function and its integral in Simulink

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Torsten
Torsten 2022-10-23
Ran in:
f = 1010;
z = @(d) sawtooth(2*pi*f*d+pi,0);
dstart = 0.0;
dend = 0.01;
delta_d = 1e-5;
d = dstart:delta_d:dend;
intz = cumtrapz(d,z(d));
hold on
yyaxis left
plot(d,z(d))
yyaxis right
plot(d,intz)
hold off

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Calculus 的更多信息

标签

产品


版本

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by