Avoid a "loop for" to add multiple "datetime" elements to a cell array
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Given the matrix "a"
% (1) create the cell array / matrix "a"
a = cell(3,3);
% (2) add the first elements to the cell array / matrix "a"
index = [1 1
2 1
3 3];
b = datetime({'00:01:35'
'00:01:11'
'00:04:21'});
idx = sub2ind(size(a),index(:,1),index(:,2));
a(idx) = num2cell(b)
I would like not to use the loop for, here below, to add multiple elements to different cells:
% (3) add two new elements:
% - one new element inside the cell [2 3]
% - one new element inside the cell [3 3]
index2 = [2 3
3 3];
new_elements = datetime({'00:01:01'
'00:01:56'});
idx2 = sub2ind(size(a),index2(:,1),index2(:,2));
for i = 1 : size(idx2,1)
a{idx2(i)} = [a{idx2(i)} new_elements(i)];
end
% Desired output, but without the loop for
a,
5 个评论
dpb
2022-10-24
Why are you making such a funky data storage pattern in the first place? That's going to be terrible to try to use for anything mixing up types/sizes (especially the types/classes) because arguments to cellfun functions are going to barf when they hit the different classes the functions aren't able to handle.
Sim
2022-10-24
dpb
2022-10-24
Would have to know the nature of the "job" -- what is the end result and why is the above organization what you came up with so far?
Data design is key in creating a functionality, but the end specifications for the result drive the whole process.
We have none of that to go on other than what looks to be an ugly mess to try to deal with as is...
Sim
2022-10-26
We don't know what "the goal" is other than the ugly-looking mess, so how can we have any suggestions about achieving same?
Is it really that your starting cell array should have been
>> N=3;
>> A=num2cell(NaT(N))
A =
3×3 cell array
{[NaT]} {[NaT]} {[NaT]}
{[NaT]} {[NaT]} {[NaT]}
{[NaT]} {[NaT]} {[NaT]}
>>
???
In that case, then at least all the elements of the cell array are datetime and you won't have the issue I raised above about having to deal with the problems of having to operate on different classes by location in the array.
But, even there I don't see a syntax without some form of a loop to do the catenation of additional elements.
回答（1 个）
Benjamin Thompson
2022-10-24
0 个投票
If you can make is an N by 1 cell array and do the assignment using parenthesis indexing and num2cell, then convert that to the J,K array size where J*K == N, then maybe it works for you?
b = cell(9,1);
b =
9×1 cell array
{0×0 double}
{0×0 double}
{0×0 double}
{0×0 double}
{0×0 double}
{0×0 double}
{0×0 double}
{0×0 double}
{0×0 double}
>> b(idx2) = num2cell(new_elements)
b =
9×1 cell array
{0×0 double }
{0×0 double }
{0×0 double }
{0×0 double }
{0×0 double }
{0×0 double }
{0×0 double }
{[24-Oct-2022 00:01:01]}
{[24-Oct-2022 00:01:56]}
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