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Get logical values from checked TreeNodes

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Daniel Dickinson
Daniel Dickinson 2022-10-26
评论： Jasmine Poppick 2024-1-25
I have made a Checkbox Tree Node as part of an app I am designing. The number of nodes may vary depending on the data fed to the app, so the nodes are created using
for a = 1:someNumber
node(a) = uitreenode(app.Tree,'Text',['Node' num2str(a)] );
end
Now I have a list of nodes. Based on user input, some are checked and some are unchecked. I want to get a logical array that represents which boxes are checked. So suppose I have 5 nodes, and nodes 2, 3 and 5 are checked. I want a one-line statement that returns
[0 1 1 0 1]
but
app.Tree.CheckedNodes
returns TreeNode objects that seem to just contain the names of the nodes. I could write some complicated search function to match the names to the list of all node names, but this seems silly. Is there an easier way? I'm open to using something other than a CheckBox Tree Node if it would be more efficient.

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Jasmine Poppick
Jasmine Poppick 2022-10-27
You can do this using ismember to query which nodes are in the CheckedNodes array:
allnodes = findall(app.Tree,"Type","uitreenode");
ismember(allnodes,app.Tree.CheckedNodes)
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Laura Ferreira
Laura Ferreira 2024-1-23
what if i want the text? I want force the check of a certain node based on its text. Instead of an array of tree node objects i would like an array of the text propreties. Can you help? Thank you
Jasmine Poppick
Jasmine Poppick 2024-1-25
You can get a cell array of the text of all of the nodes by querying the Text property:
nodes = findall(app.Tree,"Type","uitreenode");
nodeText = {nodes.Text};
However, if you want to programmatically check a node with specific text, it might be easier to find that node directly in the call to findall:
matchingNode = findall(app.Tree,"Type","uitreenode","Text","MyNodeText");
app.Tree.CheckedNodes = matchingNode;

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