What does this command (x = [(n-n0) >= 0];) do in the following code?

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Troy
Troy 2015-3-17
评论： Troy 2015-3-17
funtion[x,n]=stepseq(n0,n1,n2) n=[n1:n2]; x=[(n-n0)>=0];

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Anusha B
Anusha B 2015-3-17
Assuming n0 is a scalar and n is a vector of numbers, the statement x=[(n-n0)>=0;) will create a logical vector 'x' that will contain values of '1' and '0's based on the result of the operation (n-n0)>=0;
For example, if n0=3 and n=[1 2 3 4 5]
x=[(n-n0)>=0] will cause the vector 'x' to have the following values
x= [ 0 0 1 1 1]
Hope this helps.

更多回答（1 个）

Anusha B
Anusha B 2015-3-17
Assuming n0 is a scalar and n is a vector, the statement x=[(n-n0)>=0]; will create a logical vector 'x' that will contain values '1's or '0's based on the result of the operation (n-n0)>=0. If the condition is true for a vector element, the value returned is 1. Otherwise 0 is returned.
For example:
n0=3; n=[1 2 3 4 5]; x=[(n-n0)>=0]; % This will cause the x to have the values [0 0 1 1 1]
Hope this helps.

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