Concatenate array using square brackets
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x = zeros(1,9);
x = [1, x(1:9)];
when i run the second line multiple times, it starts to fill in the array x. I want to ask what is the functionality of the second line, and is there any documentation that describes this syntax ?
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Voss
2022-10-26
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4 个评论
Quang Nguyen
2022-10-26
% x is a 1-by-9 array (i.e., a vector) of 9 zeros:
x = zeros(1,9)
% now x is a 1 followed by the first 9 elements of what was x (i.e., 9 zeros)
x = [1, x(1:9)]
% now x is a 1 followed by the first 9 elements of what was x (i.e., a 1 and 8 zeros)
x = [1, x(1:9)]
% now x is a 1 followed by the first 9 elements of what was x (i.e., two ones and 7 zeros)
x = [1, x(1:9)]
% etc.
Perhaps it's useful to see the same code operating with a different starting vector x:
x = 1:9
x = [1, x(1:9)]
x = [1, x(1:9)]
x = [1, x(1:9)]
Considering that example, it may be more clear now, that the line x = [1, x(1:9)] does not really "replace" zeros with ones, but instead prepends a 1 to the beginning of x and removes anything after element #9, each time it is run.
Quang Nguyen
2022-10-26
Voss
2022-10-26
You're welcome!
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