Find peaks in a for loop?
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i have a 1007x94 matrix, how would I write a for loop to find the peak in every row?
采纳的回答
The maxk and mink functions (introduced in R2017b) would make this a bit more efficient. Lacking them, use sort.
Try this —
A = randn(1007, 94);
for k = 1:size(A,2)
[pks, locs] = findpeaks(A(:,k));
[~,ix] = sort(pks);
minpk{:,k} = [pks(ix(1:2)) locs(ix(1:2))];
maxpk{:,k} = [pks(ix(end-1:end)) locs(ix(end-1:end))];
end
maxpk{1} % View Result
minpk{1} % View Result
.
更多回答（1 个）
Assuming you mean maximum when you say peak.
a = randi(20, 2,10)
result = max(a,[],2)
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