Generate all permutation or possibilities

Question

Ben Nguyen 2022-10-26

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1836613-generate-all-permutation-or-possibilities

编辑： Bruno Luong 2022-10-27

I'm still fairly new to MATLAB, but got thrown at with a homework on Huffman coding. It requires to take a word, break it down to each letter, generate the all the possibilities in 3rd, 4th, and 5th order. For instance, in my case, I picked the word 'locate', then strip it down to 'l' 'o' 'c' 'a' 't' 'e'. 3rd order means I'll generate all the possilities/combinations for 3 positions out of 6 letters like 'loc' 'loa' 'lot' etc.. Same concept goes as 4th and 5th order. I had tried nchoosek function, it only give me the combinations (order matter), not all permution or possibilities. I hope it makes sense. Any guidance will be appreciated.

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Answer 1

David Hill 2022-10-26

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1836613-generate-all-permutation-or-possibilities#answer_1084618

编辑：David Hill 2022-10-26

在 MATLAB Online 中打开

x='locate';
p=[];order=3;
n=nchoosek(1:length(x),order);
for k=1:size(n,1)
    p=[p;perms(n(k,:))];
end
x(p)
ans = 120×3 char array
    'col'
    'clo'
    'ocl'
    'olc'
    'lco'
    'loc'
    'aol'
    'alo'
    'oal'
    'ola'
    'lao'
    'loa'
    'tol'
    'tlo'
    'otl'
    'olt'
    'lto'
    'lot'
    'eol'
    'elo'
    'oel'
    'ole'
    'leo'
    'loe'
    'acl'
    'alc'
    'cal'
    'cla'
    'lac'
    'lca'
    'tcl'
    'tlc'
    'ctl'
    'clt'
    'ltc'
    'lct'
    'ecl'
    'elc'
    'cel'
    'cle'
    'lec'
    'lce'
    'tal'
    'tla'
    'atl'
    'alt'
    'lta'
    'lat'
    'eal'
    'ela'
    'ael'
    'ale'
    'lea'
    'lae'
    'etl'
    'elt'
    'tel'
    'tle'
    'let'
    'lte'
    'aco'
    'aoc'
    'cao'
    'coa'
    'oac'
    'oca'
    'tco'
    'toc'
    'cto'
    'cot'
    'otc'
    'oct'
    'eco'
    'eoc'
    'ceo'
    'coe'
    'oec'
    'oce'
    'tao'
    'toa'
    'ato'
    'aot'
    'ota'
    'oat'
    'eao'
    'eoa'
    'aeo'
    'aoe'
    'oea'
    'oae'
    'eto'
    'eot'
    'teo'
    'toe'
    'oet'
    'ote'
    'tac'
    'tca'
    'atc'
    'act'
    'cta'
    'cat'
    'eac'
    'eca'
    'aec'
    'ace'
    'cea'
    'cae'
    'etc'
    'ect'
    'tec'
    'tce'
    'cet'
    'cte'
    'eta'
    'eat'
    'tea'
    'tae'
    'aet'
    'ate'

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Ben Nguyen 2022-10-26

Thank you David, your code produces what I was intended.

Any chance you can give me guidance on the second part?

I need to find the product of each posibility. For instance, I'll set l = 0.2 , o = 0.2, c = 0.2, so the product of 'loc' will be 0.2*0.2*0.2 = 0.008.

Any help will be appreciated!

Bruno Luong 2022-10-27

编辑：Bruno Luong 2022-10-27

在 MATLAB Online 中打开

Can't find where youu describe the second part in the original question, but here we go

s = 'locate'
s = 'locate'
p = [0.2 0.2 0.2 0.1 0.1 0.2]; % corresponding probability for each letter of 'locate'
s='locate'
s = 'locate'
n=3;
c=nchoosek(s,n);
c=reshape(c(:,perms(n:-1:1)')',n,[])'
c = 120×3 char array
    'loc'
    'lco'
    'olc'
    'ocl'
    'clo'
    'col'
    'loa'
    'lao'
    'ola'
    'oal'
    'alo'
    'aol'
    'lot'
    'lto'
    'olt'
    'otl'
    'tlo'
    'tol'
    'loe'
    'leo'
    'ole'
    'oel'
    'elo'
    'eol'
    'lca'
    'lac'
    'cla'
    'cal'
    'alc'
    'acl'
    'lct'
    'ltc'
    'clt'
    'ctl'
    'tlc'
    'tcl'
    'lce'
    'lec'
    'cle'
    'cel'
    'elc'
    'ecl'
    'lat'
    'lta'
    'alt'
    'atl'
    'tla'
    'tal'
    'lae'
    'lea'
    'ale'
    'ael'
    'ela'
    'eal'
    'lte'
    'let'
    'tle'
    'tel'
    'elt'
    'etl'
    'oca'
    'oac'
    'coa'
    'cao'
    'aoc'
    'aco'
    'oct'
    'otc'
    'cot'
    'cto'
    'toc'
    'tco'
    'oce'
    'oec'
    'coe'
    'ceo'
    'eoc'
    'eco'
    'oat'
    'ota'
    'aot'
    'ato'
    'toa'
    'tao'
    'oae'
    'oea'
    'aoe'
    'aeo'
    'eoa'
    'eao'
    'ote'
    'oet'
    'toe'
    'teo'
    'eot'
    'eto'
    'cat'
    'cta'
    'act'
    'atc'
    'tca'
    'tac'
    'cae'
    'cea'
    'ace'
    'aec'
    'eca'
    'eac'
    'cte'
    'cet'
    'tce'
    'tec'
    'ect'
    'etc'
    'ate'
    'aet'
    'tae'
    'tea'
    'eat'
    'eta'
[~, i] = ismember(c, s);
pc = prod(p(i),2) % this is the probability of the char-row in c
pc = 120×1
    0.0080
    0.0080
    0.0080
    0.0080
    0.0080
    0.0080
    0.0040
    0.0040
    0.0040
    0.0040

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Answer 2

Bruno Luong 2022-10-26

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1836613-generate-all-permutation-or-possibilities#answer_1084638

在 MATLAB Online 中打开

s='locate'
s = 'locate'
n=3;
c=nchoosek(s,n);
c=reshape(c(:,perms(n:-1:1)')',n,[])'
c = 120×3 char array
    'loc'
    'lco'
    'olc'
    'ocl'
    'clo'
    'col'
    'loa'
    'lao'
    'ola'
    'oal'
    'alo'
    'aol'
    'lot'
    'lto'
    'olt'
    'otl'
    'tlo'
    'tol'
    'loe'
    'leo'
    'ole'
    'oel'
    'elo'
    'eol'
    'lca'
    'lac'
    'cla'
    'cal'
    'alc'
    'acl'
    'lct'
    'ltc'
    'clt'
    'ctl'
    'tlc'
    'tcl'
    'lce'
    'lec'
    'cle'
    'cel'
    'elc'
    'ecl'
    'lat'
    'lta'
    'alt'
    'atl'
    'tla'
    'tal'
    'lae'
    'lea'
    'ale'
    'ael'
    'ela'
    'eal'
    'lte'
    'let'
    'tle'
    'tel'
    'elt'
    'etl'
    'oca'
    'oac'
    'coa'
    'cao'
    'aoc'
    'aco'
    'oct'
    'otc'
    'cot'
    'cto'
    'toc'
    'tco'
    'oce'
    'oec'
    'coe'
    'ceo'
    'eoc'
    'eco'
    'oat'
    'ota'
    'aot'
    'ato'
    'toa'
    'tao'
    'oae'
    'oea'
    'aoe'
    'aeo'
    'eoa'
    'eao'
    'ote'
    'oet'
    'toe'
    'teo'
    'eot'
    'eto'
    'cat'
    'cta'
    'act'
    'atc'
    'tca'
    'tac'
    'cae'
    'cea'
    'ace'
    'aec'
    'eca'
    'eac'
    'cte'
    'cet'
    'tce'
    'tec'
    'ect'
    'etc'
    'ate'
    'aet'
    'tae'
    'tea'
    'eat'
    'eta'