Exacting a constant range/window of values from a matrix (skipping one cell each time).

Question

Matt 2022-10-27

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https://ww2.mathworks.cn/matlabcentral/answers/1837073-exacting-a-constant-range-window-of-values-from-a-matrix-skipping-one-cell-each-time

回答： RAGHUNATHRAJU DASHARATHA 2022-10-27

Hi all,

I have a variable of values, X (1000 x 1) and want to create a separate variable, Y which is made up from values 1:24, skip one cell, then the next 24 values, skip one cell etc etc. until a certain value or the end of the matrix.

I feel like it should be reltively simple but just can't seem to quite get it right. Any help would be much appreciated.

Thanks in advance.

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Answer 1

KALYAN ACHARJYA 2022-10-27

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data=rand(1000,1);
data(25:25:1000)=[];
temp=length(data)/24;
cell_data=mat2cell(data,24*ones(1,temp))
cell_data = 40×1 cell array
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}
    {24×1 double}

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KALYAN ACHARJYA 2022-10-27

Each cell element consist of 24x1 values, the good way to handle multiple array is using cell array, as shown in the code.

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Answer 2

RAGHUNATHRAJU DASHARATHA 2022-10-27

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As per my understanding you want to skip every 25th value of a matrix.

I will try to explain it using an example below .

A=1:1000;
  B=A'
B = 1000×1
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  for i=1:38
  B(i*25)=[];
  end
  output=B
output = 962×1
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