How to XOR two cells from the same cell array?
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Hello,
I have one array of size 1x1024. I want to XOR each cell of the array. The first cell remains the same.It is as follows
Let T represent the position of each cell, then
CellT` = {Cell T XOR Cell(T-1) for T=2..1024
Cell T for T=1
Lets consider a 1x10 array.It is of the following form.
X= ['0000000000000001' '0000000000000010' '0000000000000011' '0000000000000100' '0000000000000101' '0000000000000110' '0000000000000111' '0000000000001000' '0000000000001001' '0000000000001010']
So I need to XOR the adjacent elements except the first one. Please help thanks in advance.
1 个评论
It sounds that your array with cells is just a plain matlab matrix, in which case you'd be better off calling the cells elements
Cell arrays, whose elements are cells are something very different in matlab.
采纳的回答
Michael Haderlein
2015-3-18
With "cell", do you mean you have a cell array or do you refer to the elements of a normal logical array? I suppose second, then it's just
T =
1 1 0 0 1
>> XORT=xor(T(2:end),T(1:end-1))
XORT =
0 1 0 1
In case it's really a cell array, you can either translate the cell array into a normal array (cell2mat) or apply cellfun here:
>> Tc=num2cell(T)
Tc =
[1] [1] [0] [0] [1]
>> XORTc=cellfun(@(x,y) xor(x,y),Tc(2:end),Tc(1:end-1))
XORTc =
0 1 0 1
Hope that's answering your question!
2 个评论
Abirami
2015-3-18
Michael Haderlein
2015-3-18
With respect to your modified question, you can do the following:
>> T= {'0000000000000001' '0000000000000010' '0000000000000011' '0000000000000100' '0000000000000101' '0000000000000110' '0000000000000111' '0000000000001000' '0000000000001001' '0000000000001010'};
>> Tc=cellfun(@(x) x=='1',T,'uniform',false);
>> XORTc=[Tc(1) cellfun(@(x,y) xor(x,y),Tc(2:end),Tc(1:end-1),'uniform',false)];
The first use of cellfun translates the string arrays into logical arrays and the second performs the xor along with the concatenation with the first value of Tc.
更多回答（1 个）
Guillaume
2015-3-18
If you are operating on strings of '0' and '1', then the xor operation is the same as the ~= operation plus a conversion back to string.
binstrxor = @(binstr1, binstr2) char('0' + (binstr1 ~= binstr2));
Thus:
X = {'0000000000000001' '0000000000000010' '0000000000000011' '0000000000000100' '0000000000000101' '0000000000000110' '0000000000000111' '0000000000001000' '0000000000001001' '0000000000001010'};
Xxor = cellfun(binstrxor, X(1:end-1), X(2:end), 'UniformOutput', false)
Note that the strings must be the same length (same number of bits) for ~= to work.
1 个评论
Michael Haderlein
2015-3-18
+1 - that's shorter than my solution.
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