or-function with switch
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Can you not use or in one of the cases for switch. I tried here but it did not call it at all:
I know about the case {2, 3} possibility just wondered about if or is a possibility here
here is my function:
function grade=switchletgrade1(quiz)
if quiz<0 ||quiz>4
grade='X'
else
switch quiz
case 3 || 2
grade='B'
case 4
grade='A'
otherwise
grade='C'
end
end
end
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采纳的回答
Walter Roberson
2011-10-15
No, 3||2 cannot be used in that context. Each case list is executed (unless the switch matched earlier), so 3||2 as a case label is evaluated as logical(3)||logical(2) which is true||true which is true which has the numeric value 1. Coding 3||2 as a case is thus equivalent to coding a 1 at that point.
The {} notation is the one you need for multiple possibilities.
2 个评论
Jan
2011-10-15
Please, Tor, post the code instead of screenshots.
"case 2||3" is equivalent to "case true", because "2||3" is equivalent to "logical(2)||logical(3)".
You want: "case {2, 3}". Reading the documentation is stringly recommended: "doc switch" and the Getting Started chapters.
更多回答(1 个)
William
2011-10-15
It works. You had one too many "end" statements. You might want to make it a little bit more stable by using more "=<" statements in the switch statement otherwise a 3.4 is going to be a "C"
function grade=switchletgrade1(quiz)
if quiz<0 ||quiz>4
grade='X'
else
switch quiz
case 3 || 2
grade='B'
case 4
grade='A'
otherwise
grade='C'
end
end
1 个评论
Walter Roberson
2011-10-15
Tor does *not* have too many 'end' statements. Refer to the documentation for "function", which says,
You can terminate any type of function with an end statement, but doing so is not required unless the file containing the function also contains one or more nested functions. Within this file, every function (including primary, nested, private, and subfunctions) must be terminated with an end.
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