find Maximum values in intervals of time(each 2000 values)

u = randn(1, 24001);
t = 1:numel(u);
r = 2000;
U = zeros(r,ceil(numel(u)/r));
U(1:numel(u)) = u;                                      % 'U' Matrix
T = zeros(r,ceil(numel(t)/r));
T(1:numel(t)) = t;                                      % 'T' Matrix
[max2000,idx] = max(U);
for k = 1:size(U,2)
    t2000(k) = T(idx(k),k);
end
max2000
max2000 = 1×13
    3.5442    3.4805    3.3493    3.7120    4.4885    2.9583    2.9585    3.1143    3.7602    3.0909    3.3839    3.2174    1.5598
t2000
t2000 = 1×13
        1161        3914        4518        7332        9805       10305       12787       15740       17991       19423       20578       23642       24001

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navid jafari 2022-10-30

thanks a lot.

It works.

Star Strider 2022-10-30

As always, my pleasure!

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Answer 2

Florian Bidaud 2022-10-28

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Hi,

I would do something like that

for i = 1:(length(u)-1)/2000
    maxArray(i) = max(u((i-1)*2000+1:i*2000));
end

You'll have to adjust for the last value to include the 240001st value, your last interval would be [238001:240001] instead of [238001:240000]

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navid jafari 2022-10-30

thank you.

but I couldn't use this code for my problem.

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