how to avoid repeat numbers in a row

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imola 2015-3-19

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https://ww2.mathworks.cn/matlabcentral/answers/183995-how-to-avoid-repeat-numbers-in-a-row

评论： imola 2015-3-19

采纳的回答： Sean de Wolski

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Dear All,

I have this row

A=[1 2 3 4 5 6];

I tried to find random permutation on the vector but in many cases I got a row with repetition numbers for example

z=[1 5 2 4 1 5];or z=[1 5 2 4 1 1];

I want to avoid the repetition in this code but it is totally wrong, at first I should assign the missing numbers in such way, here is [3 6].

zc=[3 6 ];
 e=size(zc,2);
   z=[1 5 2 4 1 5];
for i=1:6
    z(i)==z
  s = find((z(i)==z) == 1)
 ss=size(s,2);
 for j=2:ss  
   for   k=1:e
      z(j)=zc(k)
      end
    end
end

I don't want to use a function from matlab to get the permutation, I need to fix my row or any permutation exchange file like (perm file ). If anyone help me for it and save me I will be grateful.

regards,

Imola

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Guillaume 2015-3-19

I don't want to use a function from matlab to get the permutation:

Does that mean that you've written your own uniform number generator? Otherwise, at some point you'll have to use rand, so you just might as well use randperm.

imola 2015-3-19

yes exactly I used randperm.

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Answer 1

Sean de Wolski 2015-3-19

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[~,x] = sort(rand(1,6))

No randperm

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imola 2015-3-19

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I m sorry Sean,

 but I wanted to accept Guillaume answer and by mistake I chose yours, how I change it because his answer was great.

regards

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Answer 2

Guillaume 2015-3-19

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It seems to me that your effort would be better spent on fixing the code that generate these invalid permutation rather than fixing the permutation afterward.

Anyway, one way to do what you want:

z = [1 5 2 4 1 1];
zc = [3 6];
%build a cell array containing the indices of repeated values:
repindices = accumarray(z', 1:numel(z), [], @(v) {v(2:end)'})'; 
%convert cell array into vector:
repindices = [repindices{:}];
%replace values at indices by replacement:
z(repindices) = zc