how to avoid repeat numbers in a row

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imola
imola 2015-3-19
评论： imola 2015-3-19
Dear All,
I have this row
A=[1 2 3 4 5 6];
I tried to find random permutation on the vector but in many cases I got a row with repetition numbers for example
z=[1 5 2 4 1 5];or z=[1 5 2 4 1 1];
I want to avoid the repetition in this code but it is totally wrong, at first I should assign the missing numbers in such way, here is [3 6].
zc=[3 6 ];
e=size(zc,2);
z=[1 5 2 4 1 5];
for i=1:6
z(i)==z
s = find((z(i)==z) == 1)
ss=size(s,2);
for j=2:ss
for k=1:e
z(j)=zc(k)
end
end
end
I don't want to use a function from matlab to get the permutation, I need to fix my row or any permutation exchange file like (perm file ). If anyone help me for it and save me I will be grateful.
regards,
Imola
  2 个评论
Guillaume
Guillaume 2015-3-19
I don't want to use a function from matlab to get the permutation:
Does that mean that you've written your own uniform number generator? Otherwise, at some point you'll have to use rand, so you just might as well use randperm.

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采纳的回答

Sean de Wolski
Sean de Wolski 2015-3-19
[~,x] = sort(rand(1,6))
No randperm
  1 个评论
imola
imola 2015-3-19
I m sorry Sean,
but I wanted to accept Guillaume answer and by mistake I chose yours, how I change it because his answer was great.
regards

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更多回答（1 个）

Guillaume
Guillaume 2015-3-19
It seems to me that your effort would be better spent on fixing the code that generate these invalid permutation rather than fixing the permutation afterward.
Anyway, one way to do what you want:
z = [1 5 2 4 1 1];
zc = [3 6];
%build a cell array containing the indices of repeated values:
repindices = accumarray(z', 1:numel(z), [], @(v) {v(2:end)'})';
%convert cell array into vector:
repindices = [repindices{:}];
%replace values at indices by replacement:
z(repindices) = zc
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Guillaume
Guillaume 2015-3-19
If you're asking how to build zc:
zc = setdiff(1:6, z)
imola
imola 2015-3-19
Dear Guillaume,
I'm so sorry, by mistake I chose Sean's answer. Forgave me.
Regards

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