non-uniform symmetric grid in 1D

-10.0000 -9.9414 -9.7662 -9.4765 -9.0758 -8.5686 -7.9609 -7.2600 -6.4739 -5.6119 -4.6841 -3.7014 -2.6753 -1.6178 -0.5414 0.5414 1.6178 2.6753 3.7014 4.6841 5.6119 6.4739 7.2600 7.9609 8.5686 9.0758 9.4765 9.7662 9.9414 10.0000

plot(a, ones(size(a)),'-o')

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

abolfazl mahmoodpoor 2022-11-2

Thanks Bruno for your kind answer.

I also found this, by changing sigma it is possible to control mesh density close to the boundaries.

N = 50;

d = 1;

sigma = d/30;

x50 = d/2;

x = d./(1+exp(-(linspace(0,d,N)-x50)/sigma));

plot(x,0,'bo')

grid on

请先登录，再进行评论。

Answer 2

Walter Roberson 2022-11-2

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1841718-non-uniform-symmetric-grid-in-1d#answer_1089483

在 MATLAB Online 中打开

No, there is no simple command for it.

If you have the first half, say a row vector B, then you can build the rest as

[B, ENDVALUE-fliplr(B)]

except, that is, for the case where the last B value is exactly half-way through, in which case you do not want to duplicate that value...

You can create your own simple functions for this, but Mathworks does not provide any simple command for it.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

abolfazl mahmoodpoor 2022-11-2

Walter thanks for your kind answer,

I think I didnot asked my question correctly,

My question is following: We know that x = linspace(0,1,N) created a uniform mesh from 0 to 1 with N-1 interval in a way that \deltax = (1-0)/(N-1). So \deltax is constant everywhere, I need to have small \deltax close to the 0 and 1, but the total number of N should be the same, and when move from 0 to 0.5 or from 1 to the 0.5 \deltax should increse gardually.

I hope I could explaine it clear.

请先登录，再进行评论。