Interpolate data to present with limited size of data

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Miraboreasu
Miraboreasu 2022-11-2
编辑： William Rose 2022-11-2
Suppose I only have 35 data points, it is very expensive to run.
x=rand(5,7)
figure
imagesc(x)
axisx=[11 12 13 14 15 16 17]
axisy=[10 20 30 40 50]
Is there any way to present them smoother, using imagesc gives too pixel. Is there any interpolation?
and display the axis with my axisx and axisy

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Davide Masiello
Davide Masiello 2022-11-2
Ran in:
x=rand(5,7)
x = 5×7
0.2207 0.4751 0.9818 0.6898 0.8489 0.7640 0.3894 0.1370 0.3264 0.7110 0.4195 0.6313 0.4999 0.0168 0.9267 0.9988 0.6922 0.3023 0.1398 0.5576 0.8856 0.2924 0.5511 0.0081 0.9578 0.6766 0.4339 0.1714 0.5717 0.5432 0.3209 0.2490 0.3414 0.1640 0.6649
figure
contourf(x,'LineColor','none')
shading interp
axis equal off
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Miraboreasu
Miraboreasu 2022-11-2
编辑：Miraboreasu 2022-11-2
@William Rose
Thank you, I think I need to rephase my quesiton, but I don't if I need to post a new thread, I will ask here first.
So for this matrix,
x=rand(5,7)
each row is one variable changing
axisx=[11 12 13 14 15 16 17]
each column is another variable changing
axisy=[10 20 30 40 50]
the value of the matrix like x(1,2) is what I want to show in colorbar
What is the best way to present them? with axis
Davide Masiello
Davide Masiello 2022-11-2
编辑：Davide Masiello 2022-11-2
Ran in:
axisx = [11 12 13 14 15 16 17];
axisy = [10 20 30 40 50];
[x,y] = meshgrid(axisx,axisy);
z = rand(5,7);
[x_new,y_new] = meshgrid(linspace(axisx(1),axisx(end),100),linspace(axisy(1),axisy(end),100));
z_new = interp2(x,y,z,x_new,y_new);
contourf(x_new,y_new,z_new,linspace(min(z(:)),max(z(:)),100),'LineColor','none')
shading interp
colorbar
xlabel('x axis')
ylabel('y axis')

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