Finding the minimizer using fminunc.
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If I have function:
fv = @(x) x(1)^2 + x(1)*x(2) + (3/2)*x(2)^2 - 2*log(x(1)) - log(x(2));
How would I use the function fminunc to find the minimizer rather than the minimum value?
采纳的回答
fv = @(x) x(1)^2 + x(1)*x(2) + (3/2)*x(2)^2 - 2*log(x(1)) - log(x(2));
[minimizer,minimum_value] = fminunc(fv,[1; 1])
更多回答（1 个）
Walter Roberson
2022-11-4
If you need to find a maximum rather than a minimum then construct
nfv = @(x) -fv(x)
now minimize nfv using fminunc.
If you need to display what the maximum is remember to evaluate fv at the location of the maximum.
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