Divided difference in Newton's form error

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Daniel
Daniel 2022-11-5
编辑： Torsten 2022-11-5
Above in my function and below is my code to call function in Matlab Grader. The problem I have is that it is telling me the variable a must be a size of [1 6]. It is currently of size [1 5]. Check where the variable is assigned a value. Can anyone tell me how to adjust my a values which is also my coefficients in order to get the size [1 6]?
function a=dd(x,f)
n = 4;
a = [-5, 2, -4, 8, 3];
end
a=dd([0, 1, -1, 2, -2], [-5, -3, -15, 39, -9]);

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回答（1 个）

Torsten
Torsten 2022-11-5
Whatever your code is supposed to do, add a sixth element to the vector "a" in function "dd":
a = [-5, 2, -4, 8, 3, 6];
instead of
a = [-5, 2, -4, 8, 3];
  2 个评论
Daniel
Daniel 2022-11-5
That would actulally make the variable a have an incorrect value. This what the code is suppose to do:
input: the function f(x) is given by its values stored in the row vector f at points stored in the row vector x. output: the program dd computes the vector of the coefficients a of the interpolating polynomial in the newton form.
Torsten
Torsten 2022-11-5
编辑：Torsten 2022-11-5
output: the program dd computes the vector of the coefficients a of the interpolating polynomial in the newton form.
Ok. Then give it a try.
The lines
n = 4;
a = [-5, 2, -4, 8, 3];
don't do that.

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