Sorting of column 'folder' present in 'struct'
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I have such a 'struct' and I want to make the column 'folder' in order. How can I do this?
3 个评论
Jonas
2022-11-9
i don't understand, the column folder is already sorted correctly?
Alberto Acri
2022-11-9
Another approach is to download NATSORTFILES here:
unzip it and then use it like this:
A = 'C:\Users\Alberto\Desktop\GLOBAL';
B = dir(fullfile(A,'DATA*','*'));
B = natsortfiles(B,[],'rmdot','noext');
采纳的回答
Sounds like you want natural order sorting. There are some File Exchange submissions that do this (example). But if the format you shared is consistent across all paths, it would also be easy to use regular expressions to extract the ending numeric values and then sort those values.
This would have been easier to demonstrate if the paths were provided as text rather than a screenshot.
str = 'C:\Users\me\folderOne\folder2\docs\Data 11';
nstr = regexp(str,'\d+$','match','once');
n = str2double(nstr)
[~, sortidx] = sort(n)
Then use sortidx to sort whatever you're sorting.
2 个评论
Alberto Acri
2022-11-9
I am using these lines of code:
A = 'C:\Users\Alberto\Desktop\GLOBAL';
B = dir(fullfile(A,'DATA*','*'));
B(ismember({B.name},{'.','..'})) = [];
Within the GLOBAL folder are several "DATA #" folders where # is a number from 1 to 50.
Within each "DATA" folder there are 3 folders "a", "c" and "s".
The "DATA #" folders I would like them in order.
Adam Danz
2022-11-9
The variable str in my answer is just an example of 1 path. In your case, you'll define str as
str = {B.folder};
then you'll use sortidx from my answer B
B_sorted = B(sortidx);
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