Nul characters and wildcards in regexp

Question

Brig 2015-3-23

回答： Tijs Van Oevelen 2016-5-10

It seems to be the case that when a regular expression encounters the pattern

[0 46 0]

it always matches everything after it.

Is this a side effect explainable in any way, or just a bug?

Example:

K>> regexp(char([0 0 1 0  41 41 41 41 41 41]),char([0 '.' 0  40 40 40 40]))
ans =
     2

The expected answer would be [] because 41 should not match the 40 in the pattern.

per isakson 2015-3-23

编辑：per isakson 2015-3-23

I call it a bug. Why not report it to tech-support whether it is a real problem to your projekt or not.

Answer 1

Hi,

this bug is probably already fixed. I tested your example in several versions of Matlab:

>> regexp(char([0 0 1 0  41 41 41 41 41 41]),char([0 '.' 0  40 40 40 40]))
ans =
     2

>> regexp(char([0 0 1 0  41 41 41 41 41 41]),char([0 '.' 0  40 40 40 40]))
ans =
     2

>> regexp(char([0 0 1 0  41 41 41 41 41 41]),char([0 '.' 0  40 40 40 40]))
ans = 
     []