How to find specific elements in a matrix

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Good Day,
I have a matrix: R55 = [2,4,6,9,11;7,8,9,10,6;1,2,6,4,5;,6,9,8,5,6;1,6,5,7,5];
I would like to find the specific locations of all the 6's (rows and colums) using a for loop and using logical matrices rather than using just the "find" function.

采纳的回答

Voss
Voss 2022-11-8
R55 = [2,4,6,9,11;7,8,9,10,6;1,2,6,4,5;,6,9,8,5,6;1,6,5,7,5]
R55 = 5×5
2 4 6 9 11 7 8 9 10 6 1 2 6 4 5 6 9 8 5 6 1 6 5 7 5
val = 6;
Using a for loop:
rows = [];
columns = [];
m = size(R55,1);
for ii = 1:numel(R55)
if R55(ii) == val
rows(end+1) = mod(ii-1,m)+1;
columns(end+1) = ceil(ii/m);
end
end
rows, columns
rows = 1×6
4 5 1 3 2 4
columns = 1×6
1 2 3 3 5 5
Using two nested for loops:
rows = [];
columns = [];
[m,n] = size(R55);
for jj = 1:n
for ii = 1:m
if R55(ii,jj) == val
rows(end+1) = ii;
columns(end+1) = jj;
end
end
end
rows, columns
rows = 1×6
4 5 1 3 2 4
columns = 1×6
1 2 3 3 5 5
Using a logical matrix, without find:
is_val = R55 == val
is_val = 5×5 logical array
0 0 1 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 0 1 0 1 0 0 0
idx = 1:numel(R55);
[rows,columns] = ind2sub(size(R55),idx(is_val))
rows = 1×6
4 5 1 3 2 4
columns = 1×6
1 2 3 3 5 5

更多回答(1 个)

Walter Roberson
Walter Roberson 2022-11-8
This kind of task is usually easier to write with nested for loops over size() of the array. If you are required to use a single for loop then loop over the linear indices and ind2sub to translate to row and column

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