Reordering columns based on first row?
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Suppose I have a matrix:
A = [
5 4 1 2
0.5 0.7 0.1 0.9
0.9 0.4 0.3 0.2];
I'd like to use my first row as an index, so that my matrix is organized in an ascending order.
I know I can use sort:
[~,idx] = sort(A(1,:));
B = A(:,idx)
but this would give me a 3 by 4 matrix. I'd like a 3 by 5 matrix, such that the output looks like this:
1.0000 2.0000 0.0000 4.0000 5.0000
0.1000 0.9000 0.0000 0.7000 0.5000
0.3000 0.2000 0.0000 0.4000 0.9000
(doesn't have to be zeros as long as the column is empty)
I'd appreciate any help with this--thanks so much in advance!
采纳的回答
Using the elements of the first row of A as column indices in B:
A = [
5 4 1 2
0.5 0.7 0.1 0.9
0.9 0.4 0.3 0.2];
B = zeros(size(A,1),max(A(1,:)));
B(:,A(1,:)) = A
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