How do I replace -1.0000e+30 with NaN?

Question

Simbarashe Chidzambwa 2022-11-9

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https://ww2.mathworks.cn/matlabcentral/answers/1846748-how-do-i-replace-1-0000e-30-with-nan

评论： Steven Lord 2022-11-10

I want to replace -1.0000e+30 in an array of SST and used the following but its not working why?:

data=netcdf.open('HadISST_sst1.nc','NC_NOWRITE')
time=netcdf.getVar(data,0);
time_bnds=netcdf.getVar(data,1);
lat=netcdf.getVar(data,2);
lon=netcdf.getVar(data,3);
sst=netcdf.getVar(data,4);
sst(sst==-1.0000*1e+30)=NaN;

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Answer 1

KSSV 2022-11-9

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Let T be your array.

tol = -10^10 ; % fix this to satisfied value 
T(T<tol) = NaN ; 

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KSSV 2022-11-9

Thanks is accepting/ voting the answer. :)

Simbarashe Chidzambwa 2022-11-9

Thank you very much it worked.

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Answer 2

Steven Lord 2022-11-9

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Since I'm guessing -1e30 is an outlier in your data you could use filloutliers. I'll use a slightly smaller outlier value for this example because it makes y display more nicely.

y = 1:10;
y(7) = 100
y = 1×10
     1     2     3     4     5     6   100     8     9    10
y2 = filloutliers(y, NaN)
y2 = 1×10
     1     2     3     4     5     6   NaN     8     9    10