How do I replace -1.0000e+30 with NaN?

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Simbarashe Chidzambwa
评论： Steven Lord 2022-11-10
I want to replace -1.0000e+30 in an array of SST and used the following but its not working why?:
data=netcdf.open('HadISST_sst1.nc','NC_NOWRITE')
time=netcdf.getVar(data,0);
time_bnds=netcdf.getVar(data,1);
lat=netcdf.getVar(data,2);
lon=netcdf.getVar(data,3);
sst=netcdf.getVar(data,4);
sst(sst==-1.0000*1e+30)=NaN;

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采纳的回答

KSSV
KSSV 2022-11-9
Let T be your array.
tol = -10^10 ; % fix this to satisfied value
T(T<tol) = NaN ;

更多回答（1 个）

Steven Lord
Steven Lord 2022-11-9
Ran in:
Since I'm guessing -1e30 is an outlier in your data you could use filloutliers. I'll use a slightly smaller outlier value for this example because it makes y display more nicely.
y = 1:10;
y(7) = 100
y = 1×10
1 2 3 4 5 6 100 8 9 10
y2 = filloutliers(y, NaN)
y2 = 1×10
1 2 3 4 5 6 NaN 8 9 10

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