How to create time windows given start and stop indices

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Anas Khan
Anas Khan 2022-11-10
评论： Image Analyst 2022-11-10
I have 2 vectors of indices: 1 for start times and 1 for end times:
>> size(trainStarts)
ans =
20 1
>> size(trainEnds)
ans =
20 1
Is there a way to, without using loops, that I can create a new variable representing windows that would be like trainStarts(1) : trainEnds(1), trainStarts(2) : trainEnds(2) and so on?

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采纳的回答

Voss
Voss 2022-11-10
Ran in:
Here's one way:
trainStarts = [2 10 15];
trainEnds = [6 12 21];
result = arrayfun(@(x,y)x:y,trainStarts,trainEnds,'UniformOutput',false)
result = 1×3 cell array
{[2 3 4 5 6]} {[10 11 12]} {[15 16 17 18 19 20 21]}

更多回答（1 个）

Image Analyst
Image Analyst 2022-11-10
编辑：Image Analyst 2022-11-10
Yes, but why? What's wrong with having them in separate arrays.
for k = 1 : length(trainStarts)
thisRange = trainStarts(k) : trainEnds(k);
% Now do something with thisRange.
end
If you want to store/keep all the ranges separately you need to put them into cells because each range might be a different number of elements.
for k = 1 : length(trainStarts)
thisRange{k} = trainStarts(k) : trainEnds(k);
% Now do something with thisRange.
end
If you don't know what a cell array is see the FAQ:
https://matlab.fandom.com/wiki/FAQ#What_is_a_cell_array?
  2 个评论
Anas Khan
Anas Khan 2022-11-10
Thanks, yeah, I may not need to keep the ranges. I was just trying to keep the code as clean as possible for downstream analysis.
Image Analyst
Image Analyst 2022-11-10
Then use my first snippet rather than my second snippet or the answer you Accepted. No sense storing stuff you don't need to store.

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