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Table column of strings to a matrix.

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Daniel
Daniel 2022-11-14
回答： Steven Lord 2022-11-14
Ran in:
Hello,
i am beginer and i am struggling with matlab tables. I have a table column that contains strings with vectors inside
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
I would like to have a matrix with the numbers inside, like
B=[0 0 0 0 0 0 0 0;0 0 0 0 0 0 0 0;0 0 0 0 0 0 0 0;1 1 1 1 1 1 1 1]
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
How can i do this without using loops? Thank you in advance.
  2 个评论
Stephen23
Stephen23 2022-11-14
编辑：Stephen23 2022-11-14
"I have a table column that contains strings with vectors inside "
This looks like file importing is suboptimal. You can probably change the file importing to import numeric as numeric, which most likely would be simpler and more efficient than messing around with text like this.
Jan
Jan 2022-11-14
"I have a table column that contains strings with vectors inside" - no, there is no table. This is a column vector of strings. If the strings are interpreted as Matlab, they would be vectors, but they are not "inside".

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采纳的回答

Stephen23
Stephen23 2022-11-14
Ran in:
A = ["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
M = cell2mat(cellfun(@str2num,A,'uni',0))
M = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

更多回答（3 个）

RAGHUNATHRAJU DASHARATHA
Ran in:
As per my understanding you want to get a matrix from the string array
I will demonstarte it using the example below
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
B =extract(A,digitsPattern)
B = 4×8 string array
"0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "1" "1" "1" "1" "1" "1" "1" "1"
B=str2double(B)
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
for more information go through the link
Steven Lord
Steven Lord 2022-11-14
Ran in:
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
A2 = erase(A, ["[", "]"])
A2 = 4×1 string array
"0 0 0 0 0 0 0 0" "0 0 0 0 0 0 0 0" "0 0 0 0 0 0 0 0" "1 1 1 1 1 1 1 1"
double(split(A2, ' '))
ans = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
Jan
Jan 2022-11-14
编辑：Jan 2022-11-14
Ran in:
A = ["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"];
AC = char(A);
AC(ismember(AC, '[] ')) = [];
AC = reshape(AC, numel(A), []);
B = AC - '0'
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
Alternative:
AC = char(extract(A, digitsPattern));
B = squeeze(AC) - '0'
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

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