How do I extract a row of data from a cell array based on a string?

2015 3 25
2 个回答
回答已采纳
更新时间：2015 3 26
10 次查看（30 天）

0 个投票

I know there are similar questions like that and have reviewed most, but don't quite have it figured out yet. As an example I have a file containing information similar to below: 07/03/2010 07:15 AM 'Run' 'Race' 4 'Mile' 10/24/2010 12:00 PM 'Run' 'Hill' 4 'Mile' 11/14/2010 09:30 AM 'Run' 'Easy' 4 'Mile' I would like to extract all those rows that say are of type 'Hill'.
I've tried the following: hill_log = runlog1(cat(1,runlog1{:,4}) == 'Hill',:)
but get: Undefined function 'eq' for input arguments of type 'cell'. No doubt some basic nuance I'm missing.
Thanks

请先登录，再回答此问题。

 采纳的回答

Sean de Wolski
Sean de Wolski 2015-3-25

0 个投票

cat(1,runlog1{:,4})
This is a cell so you can't compare it to a string. Instead use strcmp which works on cells and strings in this manner. Something like:
strcmp(cat(1,runlog1{:,4}),'Hill')

更多回答（1 个）

Dave
Dave 2015-3-26

0 个投票

Still working on this a bit. I've tried the following and just get the 1st row with 'Hill'. hill_log = strcmp(runlog1{:,4}, 'Hill'); for i=1:length(hill_log); j=0; if hill_log(i)==1 j=j+1; hill_log_matrix(j,:) = runlog1(i,:) ; end end
I'm not a coder by trade, obviously, so any further hints would be appreciated.
TIA

类别

在 帮助中心 和 File Exchange 中查找有关 LaTeX 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by