Error using piecewise function

4 次查看（过去 30 天）
Engi
Engi 2022-11-16
评论： Engi 2022-11-19
Hello,
I am trying to create this piecewise function but there is an error: 'Incorrect number or types of inputs or outputs for function 'piecewise'.
Error in Q2 (line 7)
x1 = piecewise(ABSt<=1, 1-ABSt,0,0);'
this is the code:
t = linspace(-5,5,1001);
ABSt = abs(t)
x1 = piecewise(ABSt<=1, 1-ABSt,0,0);
I am trying to creat x1 = 1-abs(t) while abs(t) is smaller or equal to 1, otherwise x1=0
is anyone knows what is wrong and how to fix it?
thank you!

请先登录，再回答此问题。

采纳的回答

Torsten
Torsten 2022-11-16
编辑：Torsten 2022-11-16
Ran in:
"piecewise" works on symbolic arguments.
Define
t = linspace(-5,5,1001);
x1 = (1-abs(t)).*(abs(t)<=1);
plot(t,x1)
instead.
  3 个评论
显示 1更早的评论
Torsten
Torsten 2022-11-16
Ran in:
As I wrote, you can define piecewise functions for symbolic inputs:
syms t
f = piecewise(abs(t)<=1,1-abs(t),0)
f = 
fplot(f)
but this doesn't work for numerical inputs for t.
The .* makes it work because you must multiply the numerical vector (1-abs(t)) with the logical vector (abs(t)<=1) elementwise.
The product as written means: multiply the element 1-abs(t(i)) with 1 (for true) if abs(t(i))<=1, else with 0 (for false). The result is a vector x1 that is 1-abs(t(i)) at position i if abs(t(i)) <=1 and 0 else.
Engi
Engi 2022-11-19
Alright, thank you for your help.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by