求解超越方程。

function a =myfun(Tw2,I2,P2)
Tm=1.5;
Te=0.5;
T0=0.05;
Jw2=pi./10;
a(1)=(Jw2+atan((2*pi*Tm)./Tw2)+atan((2*pi*Te)./Tw2)+(2*pi*T0)./Tw2)-pi;
a(2)=atan(Tw2./(2*pi*I2))-Jw2;
a(3)=((100./P2)*sqrt(1+(tan(Jw2))^2)*1./sqrt(1+(Tm*2*pi./Tw2)^2)*1./sqrt(1+(0.5*2*pi./Tw2)^2))-1;
end
/*******************************
********************************/
clear
Jw22=fsolve('myfun',[2,2,3]);
不知为什么出现错误?
Subscripted assignment dimension mismatch.
Error in myfun (line 6)
a(1)=(Jw2+atan((2*pi*Tm)./Tw2)+atan((2*pi*Te)./Tw2)+(2*pi*T0)./Tw2)-pi;
Error in fsolve (line 218)
fuser = feval(funfcn{3},x,varargin{:});
Error in Test (line 2)
Jw22=fsolve('myfun',[2,2,3]);
Caused by:
Failure in initial user-supplied objective function evaluation. FSOLVE cannot continue.

 采纳的回答

givesij
givesij 2022-11-17

0 个投票

哪是未知数呀?是这样吗?
function a=myfun(x)
%x(1)=Tw2,x(2)=I2,x(3)=P2
Tm=1.5;
Te=0.5;
T0=0.05;
Jw2=pi/10;
a(1)=(Jw2+atan((2*pi*Tm)./x(1))+atan((2*pi*Te)./x(1))+(2*pi*T0)./x(1))-pi;
a(2)=atan(x(1)./(2*pi*x(2)))-Jw2;
a(3)=((100./x(3))*sqrt(1+(tan(Jw2))^2)*1./sqrt(1+(Tm*2*pi./x(1))^2)*1./sqrt(1+(0.5*2*pi./x(1))^2))-1;
end
Jw22=fsolve('myfun',[2,2,3])
Jw22 =    1.3477    0.6601    5.8678

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