How does the following loop turn out to be different from the expected 25?

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Qiandong Dong
Qiandong Dong 2022-11-18
回答： Walter Roberson 2022-11-18
Ran in:
s=0;
I=5;
for i=1:I
for j=1:i
s=s+1
end
end
s = 1
s = 2
s = 3
s = 4
s = 5
s = 6
s = 7
s = 8
s = 9
s = 10
s = 11
s = 12
s = 13
s = 14
s = 15
value(s)
Unrecognized function or variable 'value'.

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回答（1 个）

Walter Roberson
Walter Roberson 2022-11-18
Your inner loop is j=1:i . The first time that is j=1:1 . The second time it is j=1:2 . The third time it is j=1:3, then 1:4, then 1:5 . So the inner loop is going to run 1+2+3+4+5 = 15 times.

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