How would this be solved
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Walter Roberson
2022-11-20
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The tangent line of a curve has a tan() that is dy/dx, and it passes through the point of interest. Remember y = m*x + b and m = dy/dx and b is the value needed to get the straight line to pass through (x,y)
Remember that the vector derivative of a parametric curve is tangent to the curve -
syms r(theta)
r(theta)=[2+3*cos(2*theta);
-5-sin(theta/3)];
diff(r) %tangent vector
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