Unable to perform assignment because the left and right sides have a different number of elements.

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Felicia DE CAPUA 2022-11-21

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评论： Jan 2022-11-21

Hi, everyone

This is my code, but when I'm doing to run it.. appears this error:

Unable to perform assignment because the left and right sides have a different number of elements. In particular in this line: correlation(t) = corrcoef(LFP1_t, LFP2_t). But LFP1_t ed LFP2_t are both two vectors of 1000x1.

How can I fix the problem?

start_stop_plot = [871.620 1015.860];
window = 1*new_fs; % 1 second of window
start_stop_plot_points = [start_stop_plot(1)*new_fs, start_stop_plot(2)*new_fs];
correlation = zeros(start_stop_plot_points(2)-start_stop_plot_points(1),1);
for t=start_stop_plot_points(1):start_stop_plot_points(2)-window;
    
    LFP1_t = data_1(t:t+window-1);
    LFP2_t = data_2(t:t+window-1);
    correlation(t) = corrcoef(LFP1_t, LFP2_t);
end
figure
plot(new_time(start_stop_plot_points(1):start_stop_plot_points(2)),...
    correlation(start_stop_plot_points(1):start_stop_plot_points(2)),'black');
xlabel('Time (s)'); ylim([-1 1])

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Answer 1

Jan 2022-11-21

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https://ww2.mathworks.cn/matlabcentral/answers/1858498-unable-to-perform-assignment-because-the-left-and-right-sides-have-a-different-number-of-elements#answer_1107143

编辑：Jan 2022-11-21

在 MATLAB Online 中打开

"But LFP1_t ed LFP2_t are both two vectors of 1000x1." - yes, of course, but the left side of the assignment correlation(t) is a scalar.

correlation(t) = corrcoef(LFP1_t, LFP2_t)
% [1x1]        = [2 x 2]   ==> Error!

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Felicia DE CAPUA 2022-11-21

Oh, thanks. But can I resolve this? xD

Jan 2022-11-21

I assume, I cannot guess this. How would you like to solve this? It depends on what you want to implement. Currently you assume, that you can store the output of the corrcoef function in a scalar. I cannot know, what you want to do instead.

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