Creating variables in a foor loop using num2str

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Mady
Mady 2022-11-23
编辑： Stephen23 2022-12-8
Hi,
title probably says it all. I want to create variables according to the i in the loop. I just don't even know if I can incorporate the function (I've already tried num2str, eval, evalc, sprintf) into variable definition. Below is a non-working code just to illustrate what I mean to do (hopefully). This example is just for 3 different variables but later on, I need to do this for about 60 more variables. I just cannot quite put my hand on the right formulation of the loop.
Thank you for any advices
%%% years_10 = [xvalues, yvalues]... n*2 matrices
years_10=readmatrix('10_years.csv');
years_20=readmatrix('20_years.csv');
years_30=readmatrix('30_years.csv');
for i=10:10:30
years_num2str(i) = readmatrix(sprintf('%d_years.csv',i);
end
  2 个评论
Walter Roberson
Walter Roberson 2022-11-23
Why do you think this is necessary? Why not use a cell array instead?
Stephen23
Stephen23 2022-12-8
编辑：Stephen23 2022-12-8
The easy, simple, and very efficient approach is to use indexing into one array, e.g. a cell array or structure array.
Using indexing is shown in the MATLAB documentation:
https://www.mathworks.com/help/matlab/import_export/process-a-sequence-of-files.html

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采纳的回答

William Rose
William Rose 2022-11-23
编辑：William Rose 2022-11-23
Ran in:
@Jiri Kovar,
[edit: change "v" to "s" in my description, to match the code]
N=50;
for i=10:10:N, s.(strcat('a',num2str(i)))=i^2; end
disp(s)
a10: 100 a20: 400 a30: 900 a40: 1600 a50: 2500
creates a structure s with fields a10, a20, ..., a50. Each one equals a scalar. You could initialize each one to be a vector or array, if you prefer.
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Mady
Mady 2022-12-7
Thank you @William Rose for quite a handy solution. The tutorial about Dynamic variable naming is very useful, lots of new informations :)

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