Boole's Approximation
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I checked my code several times but I can not find the mistake. There is a huge difference between the exact answer and Boole's approximate value.
function Boole_approx(a,b)
a = -1;
b = 1;
N=10; %total number of intervals
h = (b-a)/(4*N); %shows the steps increment
x = a:h:b;
s=((2*h)/45)*(7*(f(a)+f(b)));
for i=1:2:N-1
s = s + ((2*h)/45)*(32*f(x(i)));
end
for i=2:4:N-2
s = s + ((2*h)/45)*(12*f(x(i)));
end
for i=4:4:N-4
s = s + ((2*h)/45)*(14*f(x(i)));
end
disp (s)
G = @(x)(tan(x)-2.*x);
exact_value = integral(G,0,pi)
end
function fx=f(x)
fx = tan(x)-2*x;
end
Answer
resuts =
0.232772096457974 -9.87116269500961
1 个评论
Image Analyst
2022-11-24
What did you pass in for a and b?
And why do you immediately ovrewrite them with -1 and 1, thus making the input arguments totally irrelevant?
回答（1 个）
Alan Stevens
2022-11-24
1 个投票
You are using Boole from -1 to 1, but the "exact" from 0 to pi. (You should plot G against x to see why your "exact" integral won't produce a sensible numerical answer).
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2022-11-24
2022-11-24
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