Boole's Approximation

1 次查看(过去 30 天)
Syed Abdul Rafay
Syed Abdul Rafay 2022-11-24
I checked my code several times but I can not find the mistake. There is a huge difference between the exact answer and Boole's approximate value.
function Boole_approx(a,b)
a = -1;
b = 1;
N=10; %total number of intervals
h = (b-a)/(4*N); %shows the steps increment
x = a:h:b;
s=((2*h)/45)*(7*(f(a)+f(b)));
for i=1:2:N-1
s = s + ((2*h)/45)*(32*f(x(i)));
end
for i=2:4:N-2
s = s + ((2*h)/45)*(12*f(x(i)));
end
for i=4:4:N-4
s = s + ((2*h)/45)*(14*f(x(i)));
end
disp (s)
G = @(x)(tan(x)-2.*x);
exact_value = integral(G,0,pi)
end
function fx=f(x)
fx = tan(x)-2*x;
end
Answer
resuts =
0.232772096457974 -9.87116269500961
  1 个评论
Image Analyst
Image Analyst 2022-11-24
What did you pass in for a and b?
And why do you immediately ovrewrite them with -1 and 1, thus making the input arguments totally irrelevant?

请先登录,再进行评论。

回答(1 个)

Alan Stevens
Alan Stevens 2022-11-24
You are using Boole from -1 to 1, but the "exact" from 0 to pi. (You should plot G against x to see why your "exact" integral won't produce a sensible numerical answer).
  1 个评论
Syed Abdul Rafay
Syed Abdul Rafay 2022-11-24
sorry I made a mistake her but it is to pi in original code. I forgot to correct it while pasting. I tried 5 to 6 time inf is the answer of boole's and 67 for exact

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Programming 的更多信息

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by