Array assembly by indexing in a loop

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Saim Ehtesham
Saim Ehtesham 2022-11-26
评论： Saim Ehtesham 2022-11-26
I have the following code:
n = 4;
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
Y1_X1 = []
for i = 1:n
Y1_X1(end) = y1_x1(i:end);
end
The idea is to form Y1_X1 such that first time, it takes n values of y1_x1 (in this case all 4), next time it takes (n-1):end values of y1_x1 (in this case last 3) and assembles these 3 infront of the first 4, and does this all the way till it gets the last value in y1_x1 and assembles it at the end of the long Y1_X1. So output of loop looks like this:
Y1_X1 =
1.0000 0.9428 0.7454 0 0.9428 0.7454 0 0.7454 0 0
Thanks

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采纳的回答

Bruno Luong
Bruno Luong 2022-11-26
编辑：Bruno Luong 2022-11-26
Ran in:
n = 4;
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
Y1_X1 = [];
for i = 1:n
Y1_X1 = [Y1_X1, y1_x1(i:end)]; % concatenate
end
Y1_X1
Y1_X1 = 1×10
1.0000 0.9428 0.7454 0 0.9428 0.7454 0 0.7454 0 0

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