Array assembly by indexing in a loop

I have the following code:
n = 4;
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
Y1_X1 = []
for i = 1:n
Y1_X1(end) = y1_x1(i:end);
end
The idea is to form Y1_X1 such that first time, it takes n values of y1_x1 (in this case all 4), next time it takes (n-1):end values of y1_x1 (in this case last 3) and assembles these 3 infront of the first 4, and does this all the way till it gets the last value in y1_x1 and assembles it at the end of the long Y1_X1. So output of loop looks like this:
Y1_X1 =
1.0000 0.9428 0.7454 0 0.9428 0.7454 0 0.7454 0 0
Thanks

 采纳的回答

n = 4;
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
Y1_X1 = [];
for i = 1:n
Y1_X1 = [Y1_X1, y1_x1(i:end)]; % concatenate
end
Y1_X1
Y1_X1 = 1×10
1.0000 0.9428 0.7454 0 0.9428 0.7454 0 0.7454 0 0

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

产品

版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by