Getting "Arrays have incompatible sizes for this operation." on this exercise
1 次查看(过去 30 天)
显示 更早的评论
Hello im trying to create a discrete time signal and im getting Arrays have incompatible sizes for this operation. Its something on z = [u1 - u2];. Any help or advice?
close all;
clear all;
clc;
clf;
AM = 19390128
k = mod(AM,5)
t = mod(AM,4)
n = -50:50;
u = [zeros(3 + k) ones(3 + k)];
u1 = [zeros(n + 2 + k) ones(n + 2 + k)];
u2 = [zeros(n - 2 - t) ones(n - 2 - t)];
delta = [1,zeros(n - t)];
x = times(6,delta);
y = [u - x];
z = [u1 - u2];
stem(z);
0 个评论
采纳的回答
Star Strider
2022-11-28
The ‘z’ assignment fails because the arrays used to calculate it are empty, likely because the first 50 elements of ‘n’ are less than or equal to zero, an ‘n’ is being used to define ‘u1’ and ‘u2’. However replacing ‘n’ with numel(n) in those assignments still results in incompatible array sizes, at least in part because a single numeric argument to zeros and ones (and similar functions) results in a matrix —
AM = 19390128
k = mod(AM,5)
t = mod(AM,4)
n = -50:50;
Sz_n = size(n)
n_pos = nnz(n>0)
u = [zeros(3 + k) ones(3 + k)];
SzU = size(u)
u1 = [zeros(n + 2 + k) ones(n + 2 + k)]
u2 = [zeros(n - 2 - t) ones(n - 2 - t)]
u1 = [zeros(numel(n) + 2 + k) ones(numel(n) + 2 + k)] % Use: numel(n)
u2 = [zeros(numel(n) - 2 - t) ones(numel(n) - 2 - t)] % Use: numel(n)
delta = [1,zeros(n - t)];
x = times(6,delta);
y = [u - x];
z = [u1 - u2];
stem(z);
I leave that for you to resolve.
.
2 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!