Using the listdlg function

Question

callum hayes 2022-11-30

1
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1867968-using-the-listdlg-function

评论： Walter Roberson 2022-12-3

I am using the listdlg function and using 'Multiple' so the user can select mulitple items. When using the 'if,elseif' or the 'case' statements, they wont work when selecting mutiple items. They will work however if i only select one item from the list. The case statement spits out the code 'SWITCH expression must be a scalar or a character vector' and the 'if' statement spits a vector when i am trying to plot multiple bar graphs.

Any help would be great thanks.

2 个评论
显示无隐藏无

Luca 2022-12-3

Same problem for me, the output is a vector but I dont know what to do with it. (Im still a newbie)

Walter Roberson 2022-12-3

@Luca

Like @Les Beckham shows, loop over the values returned by listdlg()

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Les Beckham 2022-11-30

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1867968-using-the-listdlg-function#answer_1116778

在 MATLAB Online 中打开

You probably just need to wrap your switch/case processing in a for loop. For example:

s = listdlg('ListString', {'One', 'Two', 'Three'});
for ii = 1:numel(s)
    switch s(ii)
        case 1
            % do something
        case 2
            % do something different
        case 3
            % do something else
    end
end