Solving cubic equation with imaginary numbers

2022 12 2
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更新时间：2022 12 2
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Hi everyone
I want to solve this equation by multiplying these variables with imaginary numbers and get clear result with s variable and output is in some weird form. What's wrong?
My code below .
clc;
clear;
s1 = 133.9457 + 253.416i
s2 = 133.9457 - 253.416i
s3 = 1339.457
syms s
x = solve(0.00017493*(s-s1)*(s-s2)*(s-s3))
Thanks in advance

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Stephan
Stephan 2022-12-2
编辑：Stephan 2022-12-2
Ran in:

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Ran in:
s1 = 133.9457 + 253.416i;
s2 = 133.9457 - 253.416i;
s3 = 1339.457;
syms s
x_exactly = solve(0.00017493*(s-s1)*(s-s2)*(s-s3))
x_exactly = 
x_numeric = double(x_exactly)
x_numeric =
1.0e+03 * 1.3395 + 0.0000i 0.1339 - 0.2534i 0.1339 + 0.2534i

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jayvoor
jayvoor 2022-12-2
Thank you for fast response but how can I get a cubic form with s? I want to get output like this
e.g x= a^3s + a^2s + a^s + Ai
Stephan
Stephan 2022-12-2
Ran in:
Ran in:
s1 = 133.9457 + 253.416i;
s2 = 133.9457 - 253.416i;
s3 = 1339.457;
syms s
x_exactly = expand(0.00017493*(s-s1)*(s-s2)*(s-s3))
x_exactly = 
jayvoor
jayvoor 2022-12-2
Thank you very much!! Have a good day sir :)

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