Random pulse generator
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Hello,
I'm new in Simulink and i trying to make a pulse random generator. Pulses have amplitude (+10 & -10) and width (1 ms). The signal has to be non periodic, i mean, pulses has to appear by a random series. how can i do it? I apprecitate any help. The begining of my project depend of this signal.
Thanks. Néstor.
3 个评论
Azzi Abdelmalek
2012-10-29
Check the second image (modified)
set the Amplitude of the pulse generator to 2 and substract 1
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Azzi Abdelmalek
2012-10-27
编辑:Azzi Abdelmalek
2012-10-27
use this block
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/172096/image.jpeg)
the function is
function y = fcn(u)
%#codegen
id=rand(1)
if id>0.5 & u==0
y=1
else
y=0
end
or easier
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/172097/image.png)
%
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更多回答(2 个)
Fangjun Jiang
2011-10-19
Go to Simulink Sources library, there is the Random Number block and the Uniform Random Number block.
The output of the Uniform Random Number is between 0 and 1, so you'll need to use Relational Operator block to compare it with constant such as 0.1 and 0.9, and then use Switch block to output the +10 or -10 or 0 pulse value.
3 个评论
Fangjun Jiang
2011-10-21
You can compare the random number with a constant, e.g. 0.9 and then add a zero-order holder block.
Néstor Monedero
2011-11-28
2 个评论
sneha j
2021-5-3
hi, there is a bug in ur code.
In the case that u(i)<-0.9, y(i) sets to -1 in the first if-block.
But wen it executes the 2nd if-block - if gets overwritten by y(i)=0 as u(i)<0.9, so it executes the else part of the block.
U need to club the the first if block with the 2nd if-else block into one if block as follows:
if(u(i)<-0.9)
y(i)=-1;
else if(u(i)>0.9)
y(i)=1;
else
y(i)=0;
end
Hope it works well.
sneha j
2021-5-3
hi Nestor, sorry i jus realised that the else if block doesnt work, so here is a workaround:
if(u<-0.5)
y=-10;
else
y=0;
end
if(u>0.5)
y=10;
end
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/605410/image.png)
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