Hi, I am trying to implement a 3D cylinder code, and here is the code:
nCS = 2; %number of cross section of cylinder
nNodes = 50; %number of nodes per cross section
rSC = size * ones(1, nNodes); %set length of each vertices
theta = linspace(0, 2* pi, nNodes); %set angle of each vertices
polar(theta, rSC)
zSC = linspace(0, hSC, nCS)'; %create z coordinates, with height hSC
[xSC,ySC] = pol2cart(theta, rSC); %transform from polar to cartisen
XSC = repmat(xSC, nCS, 1); %repeat for array of number of cross sections
YSC = repmat(ySC, nCS, 1);
ZSC = repmat(zSC, 1, nNodes); %repeat for number of z-layers
xSC_lid = zeros(2, nNodes); %creating the top and bottom lid
ySC_lid = zeros(2, nNodes);
zSC_lid = repmat([0, hSC], 1, nNodes);
X = [xSC_lid(1,:); XSC; xSC_lid(2,:)];
Y = [ySC_lid(1,:); YSC; ySC_lid(2,:)];
Z = [zSC_lid(1,:); ZSC; zSC_lid(2,:)];
surf(X, Y, Z)
The error message is
What is wrong and how to solve this?

 采纳的回答

Much of your code seems to be an unnecessary reinvention of the cylinder() command.
nCS = 2; %number of cross section of cylinder
nNodes = 50; %number of nodes per cross section
[X,Y,Z]=cylinder(ones(1,nCS),nNodes);
surf(X,Y,Z,'FaceAlpha',0.7)
patch('XData',X(1,:),'YData',Y(1,:), 'ZData',Z(1,:),'FaceColor','r');
patch('XData',X(nCS,:),'YData',Y(nCS,:), 'ZData',Z(nCS,:),'FaceColor','r');

6 个评论

I see, however I wish to stack 2 cylinders together, which I am thinking hard to implement through cylinder(m).
May I know if you know how to implement this?
say cylinder1 has a height of 2, and I want to have the base of cylinder2 (height 3) to be ontop of cylinder1?
Do they have different radii? Otherwise, the stacking is equivalent to taking nCS=3.
Oh you're right! I never thought of this. My model also has an ring on top of the cylinder, which has a different radii than the cylinder. Can I also use the cylinder(m) function? How do you stack the ring onto the cylinder?
Just add shifts and scalings to the X,Y,Z coordinates as appropriate
cappedCylinder(2,4,0)
cappedCylinder(4,1,4)
function cappedCylinder(r, h, z0)
nCS = 2; %number of cross section of cylinder
nNodes = 50; %number of nodes per cross section
[X,Y,Z]=cylinder(ones(1,nCS),nNodes);
X=r*X; Y=r*Y; Z=h*Z+z0;
surface(X,Y,Z,'FaceAlpha',0.5,'FaceColor','g')
patch('XData',X(1,:),'YData',Y(1,:), 'ZData',Z(1,:),'FaceColor','r');
patch('XData',X(nCS,:),'YData',Y(nCS,:), 'ZData',Z(nCS,:),'FaceColor','r');
view(3); axis equal
end
Hi! May I ask what is the function of the ones(1,nSC) in the code?
[X,Y,Z]=cylinder(ones(1,nCS),nNodes);
I am curious, because when I pass just 1 through returns me the same result. Like so:
[XSC,YSC,ZSC]=cylinder(1,nNodes);
Why do we need to pass radius 2 times? Oh and anyway I only need the top and bottom 2 slices, so I don't really know if I need the nCS there.
Hi, I got any other qusetion >< with this method is it possible to generate a hollow cylinder? like the walls have a certain thickness and the middle is void. Or would you suggest to use multicylinder for this?

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更多回答(1 个)

zSC_lid is an 1 x nNodes vector:
zSC_lid = repmat([0, hSC], 1, nNodes);
Thus it has only one row.
But you reference the second row in the command
Z = [zSC_lid(1,:); ZSC; zSC_lid(2,:)];
which does not exist.
Thus MATLAB throws an error.

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