How do I exit a for loop after logical index is found true in an array?

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Atanu
Atanu 2022-12-4
评论： Atanu 2022-12-4
I would like to exit a loop if the result is set to true in the for loop. But it always returns false if I use 'continue'. How do I resolve this?
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true;
end
% continue;
end

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采纳的回答

VBBV
VBBV 2022-12-4
use inside the if-end statement
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true
break % use inside the if - condition
end
end
  2 个评论
VBBV
VBBV 2022-12-4
编辑：VBBV 2022-12-4
If you use outside the if condition the result state may not be saved to true if this for loop is nested inside another loop which means it will restore the result state back to false. I presume, this for loop is present inside another loop, thats why result flag is being set to false again.
If you want to avoid reuslt to set false, you need to place the result flag outside of all nested loops.
Atanu
Atanu 2022-12-4
Thank you! I was using outside the if statement and that did not work. It works if I use inside if as you suggested. By the way, this for loop is the outermost loop.

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更多回答（1 个）

Steven Lord
Steven Lord 2022-12-4
continue exits the current iteration and proceeds to the next iteration.
break exits the loop entirely.

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