How can I set the values of matrix in interval <a, b>?

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Ihor
Ihor 2022-12-4
评论： DGM 2022-12-4
Generate a matrix Ru of pseudo-random floating point values from a uniform distribution, a matrix Ri of pseudo- random integer
values from a uniform distribution and a matrix Rn of pseudo-random values from a normal distribution. Let the size of all
matrices be M x N. Let the expected value of Rn be m = 8 and variance v = 3. Let the values of Ru an Ri be from the interval < a,
b > = < 4, 9 >.
Rn = rand( M, N ) ;
Ru = randn( M, N) ;
Ri = randi( [a, b], M, N ) ; % here I know how to set the interval <a, b>
  2 个评论
Stephen23
Stephen23 2022-12-4
编辑：Stephen23 2022-12-4
Original question by Ihor retrieved from Google cache:
https://web.archive.org/web/20221204175043/https://webcache.googleusercontent.com/search?q=cache:WKaFs5JO6NsJ:https://www.mathworks.com/matlabcentral/answers/1870617-how-can-i-set-the-values-of-matrix-in-interval-a-b
https://web.archive.org/web/20221204175257/https://www.mathworks.com/matlabcentral/answers/1870617-how
How can I set the values of matrix in interval <a, b>?
Generate a matrix Ru of pseudo-random floating point values from a uniform distribution, a matrix Ri of pseudo- random integer
values from a uniform distribution and a matrix Rn of pseudo-random values from a normal distribution. Let the size of all
matrices be M x N. Let the expected value of Rn be m = 8 and variance v = 3. Let the values of Ru an Ri be from the interval < a,b > = < 4, 9 >.
Rn = rand( M, N ) ;
Ru = randn( M, N) ;
Ri = randi( [a, b], M, N ) ; % here I know how to set the interval <a, b>
Rik
Rik 2022-12-4
I recovered the removed content from the Google cache (something which anyone can do). Editing away your question is very rude. Someone spent time reading your question, understanding your issue, figuring out the solution, and writing an answer. Now you repay that kindness by ensuring that the next person with a similar question can't benefit from this answer.

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DGM
DGM 2022-12-4
编辑：DGM 2022-12-4
Ran in:
Start with:
m = 500;
n = 500;
rrange = [4 9];
mn = 8;
vr = 3;
% uniform distribution with a specified range
Ru = rrange(1) + range(rrange)*rand(m,n);
[min(Ru(:)) max(Ru(:))]
ans = 1×2
4.0000 9.0000
% normal distribution with specified mean, variance
Rn = mn + sqrt(vr)*randn(m,n);
[mean(Rn(:)) var(Rn(:))]
ans = 1×2
7.9939 3.0058
% discrete uniform random integers
Ri = randi(rrange,m,n);
[min(Ri(:)) max(Ri(:))]
ans = 1×2
4 9

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