Accessing variable in a table, depending on another variable
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The output of the code is a table, containing the number and position of nodes in a maze.
Name = [];
Position = [];
number = 0;
Letter = 'N';
for j = 1 : size(is_node,2)
for i = 1 : size(is_node,1)
if is_node(i,j) == 1
number = number + 1;
Order = string(number);
name = Letter + Order;
Name = [Name;name];
position_y = i;
position_x = j;
Position = [Position;position_y,position_x];
end
end
end
node_table = table(Name,Position);
end
Output:
Name Position
_____ ________
"N1" 2 2
"N2" 4 2
"N3" 6 2
"N4" 10 2
"N5" 4 4
"N6" 6 4
"N7" 8 4
"N8" 10 4
"N9" 6 6
"N10" 8 6
"N11" 10 6
"N12" 2 8
"N13" 4 8
"N14" 6 8
"N15" 8 8
"N16" 10 8
"N17" 4 10
"N18" 6 10
"N19" 10 10
"N20" 2 12
"N21" 4 12
"N22" 6 12
"N23" 8 12
"N24" 10 12
I need to write a code that finds the number of a node without "N", depending on its position. For example: 10 6 should result in 11.
Any hint will help.
Thanks in advance.
1 个评论
采纳的回答
% Create a table:
is_node = false(12);
is_node(2,2) = true;
is_node(4,2) = true;
is_node(6,2) = true;
is_node(10,2) = true;
is_node(4,4) = true;
is_node(6,4) = true;
is_node(8,4) = true;
is_node(10,4) = true;
is_node(6,6) = true;
is_node(8,6) = true;
is_node(10,6) = true;
Name = [];
Position = [];
number = 0;
Letter = 'N';
for j = 1 : size(is_node,2)
for i = 1 : size(is_node,1)
if is_node(i,j) == 1
number = number + 1;
Order = string(number);
name = Letter + Order;
Name = [Name;name];
position_y = i;
position_x = j;
Position = [Position;position_y,position_x];
end
end
end
node_table = table(Name,Position)
% find the Name(s) where Position is position:
position = [10 6];
% one way:
idx = node_table.Position(:,1) == position(1) ...
& node_table.Position(:,2) == position(2);
node_number = node_table.Name(idx)
% another way:
idx = ismember(node_table.Position,position,'rows');
node_number = node_table.Name(idx)
1 个评论
node_number = "N11"
node_number = extractAfter(node_number,1)
And, if you want it to be numeric:
node_number = str2num(node_number)
By the way, I restored your question so that others who have a similar question in the future may benefit.
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